NUS ppl lip lai - Part 4

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yoshi_fanboy

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Hopefully this is the last post of this thread, before we move on to the NUS ppl lip lai - Part 4 thread! :D
 

napsterz

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Who knows why

0 + 1 + 2 + 3 + ... + (n - 2) + (n - 1) + n

=

n (n + 1) / 2 ? :s11:

Why ?
 

napsterz

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Then for decreasing one leh ?

Why

(2^k) + 2^(k-1) + ... + (2^1) + 0

= [ 2^(k+1) -1 ] / 2 - 1

? :s11:
 
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